[U-Boot-Users] Booting Linux stops at Starting Kernel, perhaps an endian problem

[Jean-Philippe Francois]

If your memory displaying programm reads word in memory, and then use
some printf like function to display them, then it will appear as big endian,
while the storage is little endian.

int foo;
foo = 0x01020304;
printf("0x%x\n",foo);

will display 0x01020304, but if you look at the memory address of foo, you will "see"
0x04030201

JP Francois
*********** REPLY SEPARATOR  ***********

On 04/03/2004 at 09:44 Marius Groeger wrote:

>On Thu, 4 Mar 2004, Sonia Martinez wrote:
>
>> The kernel and file system image (u-boot multi image) is loaded into
>> RAM with kermit at 0xa3100000. But, when we try to boot linux with
>> the bootm command, it stops at "Starting Kernel" (We're working with
>> Linux kernel 2.4.19 patched with -rmk7-pxa1 in eLinOS distribution).
>>
>> In order to see if something went wrong, we've compared vmlinux.bin
>> before compression and the kernel decompressed in RAM, in position
>> Load_address. We've found that the information is the same but one
>> is in big endian (in RAM) and the other one in little endian
>> (vmlinux.bin). The platform works in little endian, so this is
>> probably the problem. How can we solve it?? Is it a gunzip problem??
>
>It seems very unlikely to me that your u-boot has decompressed your kernel
>into a wrong endianess. Have double checked that you're really looking at
>what you're think you're looking at?
>
>It is much more likely that your kernel might not be properly supporting
>your board in the early boot phase and just hangs there. Depending how far
>it got, you may try to check the contents of the kernel's log_buf array
>after resetting the hardware. All the early printk()s go there before the
>serial driver is started.
>
>Regards,
>Marius
>
>-- 
>Marius Groeger <mgroeger at sysgo.com>
>Project Manager
>
>SYSGO Real-Time Solutions AG | Embedded and Real-Time Software
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