[U-Boot] [PATCH] serial: ns16550: fix different reg size access

Wolfgang Denk wd at denx.de
Fri Apr 1 09:39:22 CEST 2011


Dear Lei Wen,

In message <AANLkTindN8kSqiq28H68Rs77Dc6Pf-4MSTibAq_2dRaV at mail.gmail.com> you wrote:
> 
> > This makes no sense to me. I have never seen any 9 bit registers in
> > any processor I ever encountered in real life.
> 
> I don't mean that register is 9bit...
> I means that register, IER, is 32bit long, but 9-31th bit is reserved, and
> 0th to 8th bit is used... Maybe I don't say clearly...
> So byte access would only cover 0-7th bit, while 8th bit is not covered.
> 
> > Also, in this case the serial controller is probably not NS16550
> > compatible, because AFAICT the NS16550 uses only 8 bit wide
> > registers.
> 
> This is may be additional feature added. For another part except this
> one bit is all compatible with ns16550.

OK, so let's summarize the facts we found so far:

1. Your hardware is NOT NS16550 compatible.  It does not have the
   typical 8 bit register interface, but provides additional bits that
   somehow control non-standard functionality.

2. You say there is one additional bit (bit 9, i. e. 0x00000100) which
   must remain set to 1 which appears to be the default setting after
   power-on reset.

3. You say that the current implementation, which uses a writeb() call
   (i. e. a byte write operation) to this register would not only
   affect bits 0...7, as expected, but also clear bit 9.

   This seems somewhat unlikely to me, so please confirm that I
   understood correctly.

4. You say that writing a 32 bit value instead (i. e. using writel())
   would work for you.

   This seems also unlikely to me, as the driver just operates on 8
   bit data, and will insert only 8 bit data into the word written, so
   you will write some data word like 0x000000XX - and in this case
   (and only in this case) the 9th bit would explicitly be set to 0.

So from my understanding of the code the original version is supposed
to work on your hardware, while your patched version should definitely
NOT work.

Yet you state it's exactly vice versa.

Either I'm missing something, or you fail to provide complete
information.

Best regards,

Wolfgang Denk

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