[U-Boot-Users] Where does u-boot start when booting Linux?
wd at denx.de
Tue Oct 14 18:51:15 CEST 2003
In message <184.108.40.206.2.20031014083032.02837c80 at 192.168.1.10> you wrote:
> >There no decompress() in the Linux kernel. So U-Boot always starts
> >the Linux kernel right from the beginning.
> When compiling 82xx or 8xx kernels, you always get arch/ppc/boot/simple.
What do you mean with "you get it"? It comes with the source, yes.
But you don't have to use it.
> I think I understand. For a very long time now I have been using
> zImage.embedded for booting. When I followed the u-boot instructions I used
> "vmlinux" which doesn't contain the boot loader. Right?
Right. vmlinux does not contain the bootstral loader, all functions
of which are already present in U-Boot.
> Thanks for the info. It has pointed me in a new direction. The problem I am
> having is the serial baud-rate is fine in u-boot but wrong when the kernel
> boots. Perhaps the clock dividers are setup differently by u-boot than
> expected by the 8260 implementation?
Perhaps you don;t pass the baud-rate to the kernel? Did you try
passing something like "console=ttyS0,$(baudrate)" ?
Software Engineering: Embedded and Realtime Systems, Embedded Linux
Phone: (+49)-8142-4596-87 Fax: (+49)-8142-4596-88 Email: wd at denx.de
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