[U-Boot-Users] decoding 'program check exception trap'
Wolfgang Denk
wd at denx.de
Mon Aug 16 22:21:19 CEST 2004
In message <cfqlq9$1d9$1 at sea.gmane.org> you wrote:
>
> I have u-boot working on a custom board based on the MV64360 with a PPC
> 750GX processor. I've set the autoboot timeout to 3 secs, with the bootcmd
> to 'go 0x40004'. I have a 'serial_getc' in main_loop so that I can transfer
> a binary to the 40004 mem. location using a PCI interface via the host
> machine.
Ummm.. what _exactly_ are you doing? What has a "serial_getc in
main_loop" to do with a PCI transfer to memory? and why do you have
to do such modifications at all when all can be done using
envrionment variables?
> On timeout, u-boot tries to transfer control to the binary, but it seems
> there's some problem:
What exactly is the contents of the memory at 0x00040004 at this
time? [and how can you be sure about this?]
> Also, can this be due to some caching? It should not, 'cos there shouldn't
> have been any access to this location earlier for the data at that location
> to be cached, but one possibility that I can think of right now.
If there was no access to this location earlier, then how do you
think this location could contain executable code?
Best regards,
Wolfgang Denk
--
Software Engineering: Embedded and Realtime Systems, Embedded Linux
Phone: (+49)-8142-4596-87 Fax: (+49)-8142-4596-88 Email: wd at denx.de
Remember that Beethoven wrote his first symphony in C ...
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