[U-Boot] trying to bring linux-2.6.32.3 from RAM?

[Rick Ball]

I think you want to load the kernel to memory at 0x00000000, even though the u-boot load address is set to 0x8000 - my kernel, which I load to memory at 0x80000000 because that's where my SDRAM is, looks like this:

Load address: 0x80000000
Loading: #################################################################
         #################################################################
         #################################################################
         #################################################################
         #################################################################
         #################################################################
         ##########################
done
Bytes transferred = 2128612 (207ae4 hex)
## Booting kernel from Legacy Image at 80000000 ...
   Image Name:   Linux-2.6.29-rc3-omap1
   Image Type:   ARM Linux Kernel Image (uncompressed)
   Data Size:    2128548 Bytes =  2 MB
   Load Address: 80008000
   Entry Point:  80008000
   Verifying Checksum ... OK
   Loading Kernel Image ... OK
OK

Starting kernel ...

Uncompressing Linux........................................................................................................................................... done, booting the kernel. 


Rick

-----Original Message-----
From: u-boot-bounces at lists.denx.de [mailto:u-boot-bounces at lists.denx.de] On Behalf Of Marek Vasut
Sent: Wednesday, April 28, 2010 2:35 PM
To: u-boot at lists.denx.de
Cc: ogara
Subject: Re: [U-Boot] trying to bring linux-2.6.32.3 from RAM?

Dne St 28. dubna 2010 20:50:35 ogara napsal(a):
> Hi All,
> I am trying to bring linux from RAM. I have compiled the kernel and 
> created uImage. I bring the image over tftp into the memory and then 
> execute bootm memaddress. Unfortunately here is the output from my command line:
> 
>  tftp 0x8000 ipaddress:uImage
> Using egiga0 device
> TFTP from server ipaddress; our IP address is ipaddress; sending 
> through gateway ipaddress Filename 'uImage'.
> Load address: 0x8000
> Loading: #################################################################
>          #################################################################
>          #################################################################
>          ###################
> done
> Bytes transferred = 3132020 (2fca74 hex) bootm 0x8000 ## Booting 
> kernel from Legacy Image at 00008000 ...
>    Image Name:   Linux-2.6.32.3
>    Created:      2010-04-28  18:44:34 UTC
>    Image Type:   ARM Linux Kernel Image (uncompressed)
>    Data Size:    3131956 Bytes =  3 MB
>    Load Address: 00008000
>    Entry Point:  00008000
>    Verifying Checksum ... OK
>    XIP Kernel Image ... OK
> OK
> 
> Starting kernel ...
> 
> undefined instruction
> pc : [<00008008>]          lr : [<00647d1c>]
> sp : 005ffce8  ip : 000008e0     fp : 000006fc
> r10: 00724db0  r9 : 005fff90     r8 : 005fffcc
> r7 : 00000002  r6 : 0072372d     r5 : 00000154  r4 : 00000000
> r3 : 00008000  r2 : 00000100     r1 : 000006fc  r0 : 0001c200
> Flags: nZCv  IRQs off  FIQs off  Mode SVC_32 Resetting CPU ...
> 
> Now, the image is good for sure because I do not have issues bringing 
> this image from the hard drive. Do I need anything else (ftd or 
> ramdisc) to boot from RAM or the procedure presented is correct?
> my bootargs are:
> bootargs=console ttyS0,115200 root /dev/ram rw
> 
> Thank you for your help,
> Ogi

Hi, the image is probably corrupted ? Also, why do you load it to 0x8000 ? It's relocated anyway, but this way it has to be relocated twice) _______________________________________________
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