[U-Boot] trying to bring linux-2.6.32.3 from RAM?
ogara
radivojejovanovic at gmail.com
Wed Apr 28 23:18:48 CEST 2010
I understand your point. My memory alignment was off. So now I get:
## Booting kernel from Legacy Image at 00000000 ...
Image Name: Linux-2.6.32.3
Created: 2010-04-28 18:44:34 UTC
Image Type: ARM Linux Kernel Image (uncompressed)
Data Size: 3131956 Bytes = 3 MB
Load Address: 00008000
Entry Point: 00008000
Verifying Checksum ... OK
ERROR: can't get kernel image!
As I said before this file works of hard drive no problem (I just did binary
comparison and file matches).
Rick Ball wrote:
>
> Yes, but I think you need to load at address 0 instead of 0x8000, just
> like I load at 0x80000000 instead of 0x80008000. My kernel is also
> compiled to start at an offset of 0x8000, just like yours, but I think the
> image has 0x8000 of reserved space at the beginning (so you load it to 0,
> but it starts executing at 0x8000).
>
> I don't think the bootargs are even coming into play - you're executing a
> bad instruction at 0x8008 because you loaded the kernel at 0x8000 instead
> of 0 (so you're trying to execute the uninitialized reserved space).
>
> Try changing your tftp command to load at 0 instead of 0x8000, and I think
> it should boot.
>
> Rick
>
> -----Original Message-----
> From: u-boot-bounces at lists.denx.de [mailto:u-boot-bounces at lists.denx.de]
> On Behalf Of ogara
> Sent: Wednesday, April 28, 2010 3:26 PM
> To: u-boot at lists.denx.de
> Subject: Re: [U-Boot] trying to bring linux-2.6.32.3 from RAM?
>
>
> Rick,
> I have custom board with DRAM starting at 0x00000000 - 0x20000000 so I
> could not load it to 0x80000000 since I do not have that much memory. I
> noticed in your report that the load address is 0x80000000 but the kernel
> image was built with:
> Load Address: 80008000
> Entry Point: 80008000.
> I was wondering what does your bootm command line looks like and if yours
> bootargs look like mine?
> Ogi
>
>
> Rick Ball wrote:
>>
>> I think you want to load the kernel to memory at 0x00000000, even
>> though the u-boot load address is set to 0x8000 - my kernel, which I
>> load to memory at 0x80000000 because that's where my SDRAM is, looks like
>> this:
>>
>> Load address: 0x80000000
>> Loading:
>> #################################################################
>>
>> #################################################################
>>
>> #################################################################
>>
>> #################################################################
>>
>> #################################################################
>>
>> #################################################################
>> ##########################
>> done
>> Bytes transferred = 2128612 (207ae4 hex) ## Booting kernel from Legacy
>> Image at 80000000 ...
>> Image Name: Linux-2.6.29-rc3-omap1
>> Image Type: ARM Linux Kernel Image (uncompressed)
>> Data Size: 2128548 Bytes = 2 MB
>> Load Address: 80008000
>> Entry Point: 80008000
>> Verifying Checksum ... OK
>> Loading Kernel Image ... OK
>> OK
>>
>> Starting kernel ...
>>
>> Uncompressing
>> Linux...........................................................................................................................................
>> done, booting the kernel.
>>
>>
>> Rick
>>
>> -----Original Message-----
>> From: u-boot-bounces at lists.denx.de
>> [mailto:u-boot-bounces at lists.denx.de]
>> On Behalf Of Marek Vasut
>> Sent: Wednesday, April 28, 2010 2:35 PM
>> To: u-boot at lists.denx.de
>> Cc: ogara
>> Subject: Re: [U-Boot] trying to bring linux-2.6.32.3 from RAM?
>>
>> Dne St 28. dubna 2010 20:50:35 ogara napsal(a):
>>> Hi All,
>>> I am trying to bring linux from RAM. I have compiled the kernel and
>>> created uImage. I bring the image over tftp into the memory and then
>>> execute bootm memaddress. Unfortunately here is the output from my
>>> command line:
>>>
>>> tftp 0x8000 ipaddress:uImage
>>> Using egiga0 device
>>> TFTP from server ipaddress; our IP address is ipaddress; sending
>>> through gateway ipaddress Filename 'uImage'.
>>> Load address: 0x8000
>>> Loading:
>>> #################################################################
>>>
>>> #################################################################
>>>
>>> #################################################################
>>> ###################
>>> done
>>> Bytes transferred = 3132020 (2fca74 hex) bootm 0x8000 ## Booting
>>> kernel from Legacy Image at 00008000 ...
>>> Image Name: Linux-2.6.32.3
>>> Created: 2010-04-28 18:44:34 UTC
>>> Image Type: ARM Linux Kernel Image (uncompressed)
>>> Data Size: 3131956 Bytes = 3 MB
>>> Load Address: 00008000
>>> Entry Point: 00008000
>>> Verifying Checksum ... OK
>>> XIP Kernel Image ... OK
>>> OK
>>>
>>> Starting kernel ...
>>>
>>> undefined instruction
>>> pc : [<00008008>] lr : [<00647d1c>]
>>> sp : 005ffce8 ip : 000008e0 fp : 000006fc
>>> r10: 00724db0 r9 : 005fff90 r8 : 005fffcc
>>> r7 : 00000002 r6 : 0072372d r5 : 00000154 r4 : 00000000
>>> r3 : 00008000 r2 : 00000100 r1 : 000006fc r0 : 0001c200
>>> Flags: nZCv IRQs off FIQs off Mode SVC_32 Resetting CPU ...
>>>
>>> Now, the image is good for sure because I do not have issues bringing
>>> this image from the hard drive. Do I need anything else (ftd or
>>> ramdisc) to boot from RAM or the procedure presented is correct?
>>> my bootargs are:
>>> bootargs=console ttyS0,115200 root /dev/ram rw
>>>
>>> Thank you for your help,
>>> Ogi
>>
>> Hi, the image is probably corrupted ? Also, why do you load it to 0x8000
>> ?
>> It's relocated anyway, but this way it has to be relocated twice)
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