[U-Boot] [PATCH 1/6] usb: ehci: mx6: Add support for i.MX6SL
Igor Grinberg
grinberg at compulab.co.il
Thu Jun 19 14:56:59 CEST 2014
Hi Nikolay,
On 06/17/14 20:49, Nikolay Dimitrov wrote:
> Hi Igor,
>
> On 6/17/2014 9:26 AM, Igor Grinberg wrote:
>> That is exactly what we do already (code is on the way) and IMO what we should aim for.
> I really didn't knew this in the beginning before seeing your answers, this would be definitely easier
> to support.
>
>> For me it is just an artificial complication which prevents single binary for
>> i.MX6 based boards.
>> Don't get me wrong, I think that in your board code you can choose which
>> approach you want, whether it will be single or multi binary, but this
>> is i.MX6 (and possibly future i.MX*) USB code which can be used on many
>> i.MX6 boards.
> I definitely like the idea, no argument on this.
>
>> Again, what are we talking about? A couple of bytes?
> I think it will cost 22 additional bytes per check. Here's a rough example:
>
> (Code that just assigns the address to the struct pointer -> 10 bytes)
> p = (mx6_usb_t*)0x55667788;
> 8380: f247 7388 movw r3, #30600 ; 0x7788
> 8384: f2c5 5366 movt r3, #21862 ; 0x5566
> 8388: 60fb str r3, [r7, #12]
>
>
> (Code that checks in runtime the CPU type -> 32 bytes)
> if (is_imx6q())
> 8380: f7ff ffee bl 8360 <is_imx6q>
> 8384: 4603 mov r3, r0
> 8386: 2b00 cmp r3, #0
> 8388: d005 beq.n 8396 <main+0x26>
> {
> p = (mx6_usb_t*)0x11223344;
> 838a: f243 3344 movw r3, #13124 ; 0x3344
> 838e: f2c1 1322 movt r3, #4386 ; 0x1122
> 8392: 60fb str r3, [r7, #12]
> 8394: e004 b.n 83a0 <main+0x30>
> }
> else
> {
> p = (mx6_usb_t*)0x55667788;
> 8396: f247 7388 movw r3, #30600 ; 0x7788
> 839a: f2c5 5366 movt r3, #21862 ; 0x5566
> 839e: 60fb str r3, [r7, #12]
> }
>
> If I assume that we have 20 sub-systems in U-Boot, and each needs to check the CPU type
> in 10 places, this makes 4400 bytes difference, which is roughly the size of a moderately
> small driver in U-Boot.
This looks like a very rough estimation.
It also can be improved by various ways.
Anyway, I think that even 4K addition is an acceptable compromise for a
single binary.
> I need to say that I'm in no way expert in ARM assembly, so please
> feel free to point out any mistakes in my assumptions.
>
> Please don't get me wrong - I don't want to argue at all. I was just wondering about this topic
> and decided to check with you guys just to be sure.
No problem.
--
Regards,
Igor.
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