[U-Boot] [PATCH] generic_board: Call "checkboard" even though the root node has a "model" property

[Haikun Wang]

In case of enable CONFIG_OF_CONTROL and has a "model" property in the root node,
the board special "checkboard" will not be called.
Usually we show some useful version information in the function.
This patch enable call "checkboard" in any case.
It is not conflicting with showing "model" at the same time.

For example on LS2085AQDS:
Showing "model" only:
Model: Freescale Layerscape 2085a QDS Board

Showing "checkboard" only:
Board: LS2085E-QDS, Board Arch: V1, Board version: B, boot from vBank: 4

Showing both:
Model: Freescale Layerscape 2085a QDS Board
Board: LS2085E-QDS, Board Arch: V1, Board version: B, boot from vBank: 4

Signed-off-by: Haikun Wang <haikun.wang at freescale.com>
---
 common/board_info.c | 7 ++-----
 1 file changed, 2 insertions(+), 5 deletions(-)

diff --git a/common/board_info.c b/common/board_info.c
index 42d0641..4e5a1f7 100644
--- a/common/board_info.c
+++ b/common/board_info.c
@@ -14,8 +14,7 @@ int __weak checkboard(void)
 
 /*
  * If the root node of the DTB has a "model" property, show it.
- * If CONFIG_OF_CONTROL is disabled or the "model" property is missing,
- * fall back to checkboard().
+ * Then call checkboard().
  */
 int show_board_info(void)
 {
@@ -25,10 +24,8 @@ int show_board_info(void)
 
 	model = fdt_getprop(gd->fdt_blob, 0, "model", NULL);
 
-	if (model) {
+	if (model)
 		printf("Model: %s\n", model);
-		return 0;
-	}
 #endif
 
 	return checkboard();
-- 
2.1.0.27.g96db324