[U-Boot] [PATCH 04/28] armv8/ls2085a: Fix generic timer clock source

[Mark Rutland]

On Thu, Mar 19, 2015 at 04:45:35PM +0000, York Sun wrote:
> The timer clock is system clock divided by 4, not fixed 12MHz. This is
> common to the SoC, not board specific.
> 
> Signed-off-by: York Sun <yorksun at freescale.com>
> ---
>  README                             |    8 ++++++++
>  arch/arm/cpu/armv8/fsl-lsch3/cpu.c |   24 ++++++++++++++++++++++++
>  board/freescale/ls2085a/ls2085a.c  |   18 ------------------
>  include/configs/ls2085a_common.h   |    6 +++++-
>  4 files changed, 37 insertions(+), 19 deletions(-)
> 
> diff --git a/README b/README
> index f473515..776ebf4 100644
> --- a/README
> +++ b/README
> @@ -690,6 +690,14 @@ The following options need to be configured:
>  		exists, unlike the similar options in the Linux kernel. Do not
>  		set these options unless they apply!
>  
> +		COUNTER_FREQUENCY
> +		Generic timer clock source frequency.
> +
> +		COUNTER_FREQUENCY_REAL
> +		Generic timer clock source frequency if the real clock is
> +		different from COUNTER_FREQUENCY, and can only be determined
> +		at run time.
> +
>  		NOTE: The following can be machine specific errata. These
>  		do have ability to provide rudimentary version and machine
>  		specific checks, but expect no product checks.
> diff --git a/arch/arm/cpu/armv8/fsl-lsch3/cpu.c b/arch/arm/cpu/armv8/fsl-lsch3/cpu.c
> index 94fd147..e985181 100644
> --- a/arch/arm/cpu/armv8/fsl-lsch3/cpu.c
> +++ b/arch/arm/cpu/armv8/fsl-lsch3/cpu.c
> @@ -395,3 +395,27 @@ int arch_early_init_r(void)
>  
>  	return 0;
>  }
> +
> +int timer_init(void)
> +{
> +	u32 __iomem *cntcr = (u32 *)CONFIG_SYS_FSL_TIMER_ADDR;
> +	u32 __iomem *cltbenr = (u32 *)CONFIG_SYS_FSL_PMU_CLTBENR;
> +#ifdef COUNTER_FREQUENCY_REAL
> +	unsigned long cntfrq = COUNTER_FREQUENCY_REAL;
> +
> +	/* Update with accurate clock frequency */
> +	asm volatile("msr cntfrq_el0, %0" : : "r" (cntfrq) : "memory");
> +#endif

Is this executed on all CPUs, or do secondary CPUs have CNTFRQ
programmed with the correct value elsewhere?

Mark.