[U-Boot] [PATCH] powerpc: e6500: Lock/unlock 1 cache instead of L1 as init_ram
Ruchika Gupta
ruchika.gupta at nxp.com
Thu Mar 2 08:42:19 UTC 2017
Fir E6500 cores, L2 cache has been used as init_ram. L1 cache is a write
through cache on E6500.If lines are not locked in both L1 and L2 caches,
crashes are observed during secure boot. This patch locks/unlocks both L1
as well as L2 cache to prevent the crash.
Signed-off-by: Ruchika Gupta <ruchika.gupta at nxp.com>
---
arch/powerpc/cpu/mpc85xx/start.S | 6 ++++--
1 file changed, 4 insertions(+), 2 deletions(-)
diff --git a/arch/powerpc/cpu/mpc85xx/start.S b/arch/powerpc/cpu/mpc85xx/start.S
index c3e1234..b9a4cb5 100644
--- a/arch/powerpc/cpu/mpc85xx/start.S
+++ b/arch/powerpc/cpu/mpc85xx/start.S
@@ -1145,8 +1145,9 @@ switch_as:
li r0,0
1:
dcbz r0,r3
-#ifdef CONFIG_E6500 /* Lock/unlock L2 cache instead of L1 */
+#ifdef CONFIG_E6500 /* Lock/unlock L2 cache long with L1 */
dcbtls 2, r0, r3
+ dcbtls 0, r0, r3
#else
dcbtls 0, r0, r3
#endif
@@ -1790,8 +1791,9 @@ unlock_ram_in_cache:
slwi r4,r4,(10 - 1 - L1_CACHE_SHIFT)
mtctr r4
1: dcbi r0,r3
-#ifdef CONFIG_E6500 /* lock/unlock L2 cache instead of L1 */
+#ifdef CONFIG_E6500 /* lock/unlock L2 cache long with L1 */
dcblc 2, r0, r3
+ dcblc 0, r0, r3
#else
dcblc r0,r3
#endif
--
1.9.1
More information about the U-Boot
mailing list