[PATCH 3/3] efi_selftest: implement exception test for sandbox

[Heinrich Schuchardt]

Provide a unit test that causes an illegal instruction to occur.

The test can be run with the following commands:

    => setenv efi_selftest exception
    => bootefi selftest

This might be the output:

    Executing 'exception'
    EFI application triggers exception.
    Illegal instruction
    pc = 0x1444d016, pc_reloc = 0xffffaa078e8dd016
    UEFI image [0x0000000000000000:0xffffffffffffffff] '/\selftest'
    UEFI image [0x000000001444b000:0x0000000014451fff] pc=0x2016 '/bug.efi'
    Resetting ...

It would tell us that the exception was triggered by an instruction
0x2016 bytes after the load address of the binary with filename /bug.efi.

Signed-off-by: Heinrich Schuchardt <xypron.glpk at gmx.de>
---
 lib/efi_selftest/efi_selftest_miniapp_exception.c | 2 ++
 1 file changed, 2 insertions(+)

diff --git a/lib/efi_selftest/efi_selftest_miniapp_exception.c b/lib/efi_selftest/efi_selftest_miniapp_exception.c
index 63c63d75f1..59b7e5100a 100644
--- a/lib/efi_selftest/efi_selftest_miniapp_exception.c
+++ b/lib/efi_selftest/efi_selftest_miniapp_exception.c
@@ -33,6 +33,8 @@ efi_status_t EFIAPI efi_main(efi_handle_t handle,
 	asm volatile (".word 0xe7f7defb\n");
 #elif defined(CONFIG_RISCV)
 	asm volatile (".word 0xffffffff\n");
+#elif defined(CONFIG_SANDBOX)
+	asm volatile (".word 0xffffffff\n");
 #elif defined(CONFIG_X86)
 	asm volatile (".word 0xffff\n");
 #endif
--
2.28.0