[U-Boot-Users] Re: mkimage multi file use?
tguilliams at san.rr.com
Mon Aug 18 20:24:44 CEST 2003
Wolfgang Denk wrote:
>Sorry, I have no idea. If really needed, I can arrange to
>(temporarily) put a copy of the U-Boot archive on our FTP server (the
>bzip2ed tarball for U-Boot-Users is 22 MB, and 40 MB for PPCBoot).
OK, well I may take you up on that but I'll get back to you. I hate
having to ask questions I know have been answered already.
> bash$ mkimage -T multi -C gzip -a 0 -e 0 -n 'test multifile' \
> -d /path/to/kernel_image:/path/to/ramdisk_image uMulti
Hmmm... include/image.h talks about having byte counts in there as
well. Maybe I'm just confused. I'll recheck it.
>See the README (section "More About U-Boot Image Types") for the file
>format. This explains that with a mutlifile image with a kernel and a
>ramdisk you will have to skip a total of 76 bytes of header
>information (64 for U-Boot header + 4 for kernel size + 4 for ramdisk
>size + 4 for terminating null).
Thank you. Very helpful. Can't believe I missed the README reference!
>So I recommend a three step approach:
> bash$ mkimage -l uMulti
> Image Name: Linux-2.4.4-2003-04-05 Multiboot
> Created: Sun Apr 6 12:44:18 2003
> Image Type: PowerPC Linux Multi-File Image (gzip compressed)
> Data Size: 2610664 Bytes = 2549.48 kB = 2.49 MB
> Load Address: 0x00000000
> Entry Point: 0x00000000
> Image 0: 715859 Bytes = 699 kB = 0 MB
> Image 1: 1894792 Bytes = 1850 kB = 1 MB
> bash$ dd if=uMulti bs=76 skip=1 of=foo
> 34350+1 records in
> 34350+1 records out
> bash$ dd if=foo of=kernel.gz bs=715859 count=1
> 1+0 records in
> 1+0 records out
> bash$ gzip -vt kernel.gz
> kernel.gz: OK
>The "bs=715859" uses the kernel data size as printed by the "mkimage
Very much appreciated. Thanks again!
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