[U-Boot-Users] copy to flash ... outside available flash
Thomas Ruschival
ruschi79 at gmx.net
Mon Nov 13 12:56:25 CET 2006
Hi Group,
I am trying to install a Ramdiskimage into the flash of a TQM823L Board.
Somehow it seems uboot has problems to copy a image lager than 0x100000
Bytes into flash. Here is my flashinfo:
Bank # 1: AMD AM29LV160B (16 Mbit, bottom boot sect)
Size: 4 MB in 35 Sectors
Sector Start Addresses:
40000000 (RO) 40008000 (RO) 4000C000 (RO) 40010000 (RO) 40020000 (RO)
40040000 40060000 40080000 400A0000 400C0000
400E0000 40100000 40120000 40140000 40160000
40180000 401A0000 401C0000 401E0000 40200000
40220000 40240000 40260000 40280000 402A0000
402C0000 402E0000 40300000 40320000 40340000
40360000 40380000 403A0000 403C0000 403E0000
Bank # 2: AMD AM29LV160B (16 Mbit, bottom boot sect)
Size: 4 MB in 35 Sectors
Sector Start Addresses:
40400000 40408000 4040C000 40410000 40420000
40440000 40460000 40480000 404A0000 404C0000
404E0000 40500000 40520000 40540000 40560000
40580000 405A0000 405C0000 405E0000 40600000
40620000 40640000 40660000 40680000 406A0000
406C0000 406E0000 40700000 40720000 40740000
40760000 40780000 407A0000 407C0000 407E0000
This means I have 8 MB o flash. I can copy a Block of 0xFFFFF Bytes from
the RAM for example to 0x40100000. and I can copy the same Block to
0x40200000 or to 0x40300000.
But if I copy a block that is larger than 0xFFFFF to any location it claims
that I copy outside available Flash. This is stupid and wrong.
Ramdisk image size was 0x18CFC9
Baseaddress: 0x40100000
ramdisk size: + 0x0018CFC9
------------------------------
end address 0x4028CFC9
And this adress is surely not outside my flash. What is going on here?
BTW I use U-Boot 1.1.4 (Sep 18 2006 - 13:38:13) on a PPC823 with 16MB RAM
and 8 MB Flash.
Thanks for any input!
Thomas
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