[U-Boot-Users] reserving RAM via bootargs
Surya Ravikiran
koduks at gmail.com
Mon Oct 22 23:38:15 CEST 2007
I have a 256MB SDRAM, and setting the mem=252m for somereason results
in the kernel using a total memory of 186MB, can anyone comment on why
this would be
hapenning?
During bootup this is what I see:
Memory CAM mapping: CAM0=64Mb, CAM1=64Mb, CAM2=64Mb residual: 48Mb
Memory: 191232k available (2628k kernel code, 800k data, 128k init, 0k highmem)
and after bootup: cat /proc/meminfo gives this..
MemTotal: 191404 kB
MemFree: 172372 kB
Buffers: 0 kB
Cached: 10276 kB
SwapCached: 0 kB
Active: 8720 kB
Inactive: 3836 kB
HighTotal: 0 kB
HighFree: 0 kB
LowTotal: 191404 kB
LowFree: 172372 kB
SwapTotal: 0 kB
SwapFree: 0 kB
Dirty: 76 kB
Writeback: 0 kB
Mapped: 5464 kB
Slab: 4824 kB
CommitLimit: 95700 kB
Committed_AS: 6644 kB
PageTables: 288 kB
VmallocTotal: 786144 kB
VmallocUsed: 476 kB
VmallocChunk: 785292 kB
thanks
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