[U-Boot-Users] reserving RAM via bootargs

Surya Ravikiran koduks at gmail.com
Mon Oct 22 23:38:15 CEST 2007


I have a 256MB SDRAM, and setting the mem=252m for somereason results
in the kernel using a total memory of 186MB, can anyone comment on why
this would be
hapenning?

During bootup this is what I see:
Memory CAM mapping: CAM0=64Mb, CAM1=64Mb, CAM2=64Mb residual: 48Mb
Memory: 191232k available (2628k kernel code, 800k data, 128k init, 0k highmem)

and after bootup: cat /proc/meminfo gives this..
MemTotal:       191404 kB
MemFree:        172372 kB
Buffers:             0 kB
Cached:          10276 kB
SwapCached:          0 kB
Active:           8720 kB
Inactive:         3836 kB
HighTotal:           0 kB
HighFree:            0 kB
LowTotal:       191404 kB
LowFree:        172372 kB
SwapTotal:           0 kB
SwapFree:            0 kB
Dirty:              76 kB
Writeback:           0 kB
Mapped:           5464 kB
Slab:             4824 kB
CommitLimit:     95700 kB
Committed_AS:     6644 kB
PageTables:        288 kB
VmallocTotal:   786144 kB
VmallocUsed:       476 kB
VmallocChunk:   785292 kB


thanks




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