[U-Boot] [PATCH] test/py: only check for SPL signature if SPL uses serial output

Stephen Warren swarren at wwwdotorg.org
Tue Feb 16 17:39:03 CET 2016


On 02/16/2016 05:13 AM, Heiko Schocher wrote:
> check for U-Boot SPL signature only if SPL really has
> a serial output. So check if CONFIG_SPL_SERIAL_SUPPORT
> is active in board config.

Nit: That's wrapped really narrow. Any chance of wrapping to more like 
72-74 characters?

> diff --git a/test/py/u_boot_console_base.py b/test/py/u_boot_console_base.py
> index bc2bd76..f888d5c 100644

>               if self.config.buildconfig.get('config_spl', False) == 'y':
> -                m = self.p.expect([pattern_u_boot_spl_signon] + self.bad_patterns)
> -                if m != 0:
> -                    raise Exception('Bad pattern found on console: ' +
> -                                    self.bad_pattern_ids[m - 1])
> +                if self.config.buildconfig.get('config_spl_serial_support',
> +                                               False) == 'y':
> +                    m = self.p.expect([pattern_u_boot_spl_signon] +
> +                                      self.bad_patterns)
> +                    if m != 0:
> +                        raise Exception('Bad pattern found on console: ' +
> +                                        self.bad_pattern_ids[m - 1])

Conceptually this change looks fine. Rather than using nested ifs, why 
not write "if a and b:" and so avoid adding an extra indent level? I'd 
also introduce some variables to shorten the text a bit:

bcfg = u_boot_console.config.buildconfig
if bcfg.get('config_spl', 'n') == 'y' and
         bcfg.get('config_spl_serial_support', 'n') == 'y':
     ...

or:

bcfg = u_boot_console.config.buildconfig
config_spl = bcfg.get('config_spl', 'n') == 'y'
config_spl_serial_support = bcfg.get('config_spl_serial_support',
     'n') == 'y'
if config_spl and config_spl_serial_support:
     ...



More information about the U-Boot mailing list