[U-Boot] [PATCH] test/py: only check for SPL signature if SPL uses serial output
Stephen Warren
swarren at wwwdotorg.org
Tue Feb 16 17:39:03 CET 2016
On 02/16/2016 05:13 AM, Heiko Schocher wrote:
> check for U-Boot SPL signature only if SPL really has
> a serial output. So check if CONFIG_SPL_SERIAL_SUPPORT
> is active in board config.
Nit: That's wrapped really narrow. Any chance of wrapping to more like
72-74 characters?
> diff --git a/test/py/u_boot_console_base.py b/test/py/u_boot_console_base.py
> index bc2bd76..f888d5c 100644
> if self.config.buildconfig.get('config_spl', False) == 'y':
> - m = self.p.expect([pattern_u_boot_spl_signon] + self.bad_patterns)
> - if m != 0:
> - raise Exception('Bad pattern found on console: ' +
> - self.bad_pattern_ids[m - 1])
> + if self.config.buildconfig.get('config_spl_serial_support',
> + False) == 'y':
> + m = self.p.expect([pattern_u_boot_spl_signon] +
> + self.bad_patterns)
> + if m != 0:
> + raise Exception('Bad pattern found on console: ' +
> + self.bad_pattern_ids[m - 1])
Conceptually this change looks fine. Rather than using nested ifs, why
not write "if a and b:" and so avoid adding an extra indent level? I'd
also introduce some variables to shorten the text a bit:
bcfg = u_boot_console.config.buildconfig
if bcfg.get('config_spl', 'n') == 'y' and
bcfg.get('config_spl_serial_support', 'n') == 'y':
...
or:
bcfg = u_boot_console.config.buildconfig
config_spl = bcfg.get('config_spl', 'n') == 'y'
config_spl_serial_support = bcfg.get('config_spl_serial_support',
'n') == 'y'
if config_spl and config_spl_serial_support:
...
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