[U-Boot-Users] How to specify the size of bin?

甜瓜 littlesweetmelon at gmail.com
Fri May 16 07:31:03 CEST 2008


2008/5/16 Stefan Roese <sr at denx.de>:
> On Friday 16 May 2008, 甜瓜 wrote:
>>      I know it is a newbie question. Any hint from you are welcome.
>> In default, u-boot 1.1.5, "make walut_config && make all" will
>> generate a 256KB bin.
>> The last 4 bytes of the bin is a jump instruction to the entry point
>> of u-boot.Is that right?
>
> Yes, this is correct.
>
>> But my ppc405GP walnut board has 512KB flash for holding u-boot.
>
> All Walnut boards have 512k of NOR FLASH. Do you really have an original
> IBM/AMCC Walnut or a different custom 405GP board?
Yes, my board is a custom board DHT-Walut with 32MB SDRAM and
512k of boot flash AMD 29LV040B. Details are listed in:
    http://elinux.org/DHT-Walnut

>> I wonder
>> how to build a 512KB bin?
>
> Generally this is possible. You need to change CONFIG_MONITOR_LEN &
> CFG_MONITOR_BASE in include/configs/walnut.h. And TEXT_BASE in
> board/amcc/walnut/config.mk.

Thank you very much. That's exact what I need!

>> Is there any OPTION/SETTING targeting this
>> problem? Anything else
>> I should take care?
>
> But please don't forget that the environment is also stored in the NOR FLASH.
> And by changing the U-Boot size to 512k you leave no space for the
> environment.

Do you mean that environment settings (eg: ip_addr, ethaddr...) are
stored sperately
from the bin? In my mind (with guess :p), env should be defined in bin
code or data
section, and it will be compiled together with other codes to form a single bin.

> So why exactly do you want to change the U-Boot image size?
Well. The reason is:
1. Both default config of u-boot and a DHT-Walut-patched config
generate 256KB bin,
but the flash on board is 512KB. So I think I should get a 512KB bin
for flash writing.
2. The contents in the flash on my board is totally corrupted by
accident. It means
the important last-4-bytes should be rewritten to a proper state.
3. Currenly, I have to use special hardware to write bin into flash.
Therefore 256KB bin
will only overwrite the first half. The last-4-bytes in the end of
flash is still the old value.
Booting will definitely fail.

> Best regards,
> Stefan
>
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Thank you for your reply.
---
ShenLei


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