[U-Boot] how to make mkimage command work?

[Wolfgang Denk]

Dear apple pie,

In message <SNT139-W44162AFF85311A54D1D4AE3190 at phx.gbl> you wrote:
> 
> 
> Please correct me if I am wrong. From what I understand, u-boot itself is relocated to RAM by calling 
> the procedure: relocate_code at the end of the procedure: board_init_f . 

Right.

> There is a need for me to load an executable to a static address (say, 0x82xx_xxxx) in RAM such that 
> control could be passed to this executable from U-boot. How could this be accomplished, with the
> limitation that:

Just tell the linker that this is your load address when liniking your
binary.

> Could u-boot be used to relocate the said executable to the address: 0x82xx_xxxx? u-boot does not

No, U-Boot cannot do this.

> From a u-boot user group, I have learned that by using the command: "mkimage" it would be able to package a raw
> image into a blob understood by u-boot. I have discovered a few "mkimage" files, such as mkimage.o, mkimage, other
> than mkimage.c, mkimage.h and mkimage.l. But, I soon found out that I could not execute the command: mkimage.

Did you ever try to read the U-Boot manual? mkimage even has it's own
man page entry in doc/

> What should I do in order to execute the command? There isn't a file called mkimage.bin generated!!

Unix commands normally don't have any such ".bin" suffixes.

Best regards,

Wolfgang Denk

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